(x^3+4x^2-12x)/4x

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Solution for (x^3+4x^2-12x)/4x equation: 


x in (-oo:+oo)

x*((x^3+4*x^2-(12*x))/4) = 0

x*((x^3+4*x^2-12*x)/4) = 0

(x*(x^3+4*x^2-12*x))/4 = 0

x^3+4*x^2-12*x = 0

x*(x^2+4*x-12) = 0

x^2+4*x-12 = 0

DELTA = 4^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-4)/(1*2) or x = (-64^(1/2)-4)/(1*2)

x = 2 or x = -6

x*(x+6)*(x-2) = 0

(x^2*(x+6)*(x-2))/4 = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-2 )

x-2 = 0 // + 2

x = 2

( x )

x = 0

x in { -6, 2, 0, 0 }

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